Factor this expression completely, then place the factors in the proper location on the grid. 5x3 + 40y6

For this case we have the following expression:
5x3 + 40y6
Common factor 5:
5 (x3 + 8y6)
Factoring the expression within the parenthesis we have:
5 ((x + 2y2) (x2 - 2xy2 + 4y4))
Answer:
The factored expression is given by:
5 ((x + 2y2) (x2 - 2xy2 + 4y4))

Answer Link

windyyork windyyork · Answer 2 · 2019-07-03T11:15:48+02:00

Answer: The expression after completely factorised form is

[tex]5[(x+2y^2)(x^2+4y^4-2xy^2)][/tex]

Step-by-step explanation:

Since we have given that

[tex]5x^3 + 40y^6[/tex]

We need to factorise it completely:

[tex]5x^3 + 40y^6\\\\=5(x^3+8y^6)\\\\=5((x)^3+(2y^2)^3)\\\\=5[(x+2y^2)(x^2+4y^4-2xy^2)]\ (\because\ a^3+b^3=(a+b)(a^2+b^2-ab))[/tex]

Hence, the expression after completely factorised form is

[tex]5[(x+2y^2)(x^2+4y^4-2xy^2)][/tex]