mbrosky4 mbrosky4
  • 03-10-2016
  • Mathematics
contestada

x^3 - 3 x^2 + 2 x - 6 > 0

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apologiabiology
apologiabiology apologiabiology
  • 03-10-2016
factor
group them

(x^3-3x^2)+(2x-6)>0
factor
(x^2)(x-3)+(2)(x-3)>0
we see a common factor of (x-3) so undistribute that
(x-3)(x^2+2)>0
set each greater than zero
x-3>0
x>3

x^2+2>0
x^2>-2
true for all real numbers because the square of any real number is always 0 or positive


the answer is all real numbers will work

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