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03-11-2020
SAT

contestada

if 3 is a root of the function f(x)=x^2+13x+c and c is a constant, what is the value of c?

Respuesta :

03-11-2020

Answer:

C would be -45

Explanation:

3 is the root basically means if you solve for x, x would equal to 3. So to find c you just have to replace x by 3.

F(3)=3^2+13(3)+c

Now you just have to solve for c

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