Juljulp8 Juljulp8
  • 03-02-2020
  • Chemistry
contestada

Convert the given amount as noted.
1.51 times 10^24 formula units of Iron (II) hydroxide to grams

Respuesta :

Eduard22sly
Eduard22sly Eduard22sly
  • 03-02-2020

Answer: 225.75g

Explanation:

Molar Mass of Fe(OH)2 = 56 + 2(16 + 1) = 56 + 2(17) = 56 + 34 = 90g/mol

1mole(90g) of Fe(OH)2 contained 6.02x10^23 units.

Therefore, Xg of Fe(OH)2 will contain 1.51x10^24 units

Xg of Fe(OH)2 = (90x1.51x10^24)/6.02x10^23 = 225.75g

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